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Q. Let the positive numbers $a, b, c, d$ be in $A.P$. Then
$\frac{1}{abc}, \frac{1}{abd}, \frac{1}{acd}, \frac{1}{bcd}$ are in

Sequences and Series

Solution:

$a, b, c, d$ are in $A. P$.
Reversing the terms, $d, c, b, a$ are also in $A. P$.
Dividing each term by $a b c d$,
$ \frac{1}{abc}, \frac{1}{abd}, \frac{1}{acd}, \frac{1}{bcd}$ are in $A. P.$