Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be

Question

Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be (A) 27.2 eV (B) 23.8 eV (C) 12.6 eV (D) 10.2 eV

Tardigrade Admin · Accepted Answer

In ground state TE =-13.6 eV In first excited state, TE =-3.4 eV, i.e. 10.2 eV above the ground state. If ground state energy is taken as zero, the total energy in first excited state =10.2 eV

Q. Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be

27.2 eV

23.8 eV

12.6 eV

10.2 eV

In ground state $TE = - 13.6 e V$
In first excited state, $TE = - 3.4 e V$ , i.e. $10.2 e V$ above the ground state.
If ground state energy is taken as zero, the total energy in first excited state $= 10.2 e V$

Q. Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be

27.2 eV

23.8 eV

12.6 eV

10.2 eV

In ground state TE=−13.6eV In first excited state, TE=−3.4eV, i.e. 10.2eV above the ground state. If ground state energy is taken as zero, the total energy in first excited state =10.2eV

In ground state $TE = - 13.6 e V$
In first excited state, $TE = - 3.4 e V$ , i.e. $10.2 e V$ above the ground state.
If ground state energy is taken as zero, the total energy in first excited state $= 10.2 e V$