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  4. Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be

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Q. Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be

Atoms

Solution:

In ground state $TE =-13.6\, eV$
In first excited state, $TE =-3.4\, eV$, i.e. $10.2\, eV$ above the ground state.
If ground state energy is taken as zero, the total energy in first excited state $=10.2\, eV$