Let P = (x, y): x2 + y2 = 1, x, y ∈ R . Then, P is

Question

Let P = (x, y): x2 + y2 = 1, x, y ∈ R . Then, P is (A) Reflexive (B) Symmetric (C) Transitive (D) Anti-symmetric

Tardigrade Admin · Accepted Answer

The relation is not reflexive and transitive but it is symmetric, because x2 + y2 = 1 ⇒ y2 + x2 = 1

Q. Let $P = {(x$ , $y)$ : $x^{2} + y^{2} = 1$ , $x$ , $y \in R}$ . Then, $P$ is