1. Tardigrade
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  3. Mathematics
  4. Let P = (x, y): x2 + y2 = 1, x, y ∈ R . Then, P is

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Q. Let $P = \{(x$, $y)$ : $x^2 + y^2 = 1$, $x$, $y \in R\}$. Then, $P$ is

Relations and Functions - Part 2

Solution:

The relation is not reflexive and transitive but it is symmetric, because
$x^2 + y^2 = 1$
$ \Rightarrow y^2 + x^2 = 1$