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Question
Mathematics
Let f be a twice differentiable function defined on R such that f (0)=1, f'(0)=2 and f'(x)≠ 0 for all x ∈ R. If | beginarrayccf(x) f'(x) f'(x) f''(x) endarray|=0, for all x ∈ R, then the value of f (1) lies in the interval:
Q. Let
f
be a twice differentiable function defined on
R
such that
f
(
0
)
=
1
,
f
′
(
0
)
=
2
and
f
′
(
x
)
=
0
for all
x
∈
R
. If
∣
∣
f
(
x
)
f
′
(
x
)
f
′
(
x
)
f
′′
(
x
)
∣
∣
=
0
,
for all
x
∈
R
,
then the value of
f
(
1
)
lies in the interval:
4455
252
JEE Main
JEE Main 2021
Differential Equations
Report Error
A
(9,12)
B
(6,9)
C
(0,3)
D
(3,6)
Solution:
f
(
x
)
f
′′
(
x
)
−
(
f
′
(
x
)
)
2
=
0
f
′
(
x
)
f
′′
(
x
)
=
f
(
x
)
f
′
(
x
)
ln
(
f
′
(
x
)
)
=
ln
f
(
x
)
+
ln
c
f
′
(
x
)
=
c
f
(
x
)
f
(
x
)
f
′
(
x
)
=
c
lnf
(
x
)
=
c
x
+
k
1
f
(
x
)
=
k
e
c
x
f
(
0
)
=
1
=
k
f
′
(
0
)
=
c
=
2
f
(
x
)
=
e
2
x
f
(
1
)
=
e
2
∈
(
6
,
9
)