Question

Let $ABCD$ be a trapezium, in which $AB$ is parallel to $CD,AB=11,BC=4,CD=6$ and $DA=3$. The distance between $AB$ and $CD$ is

• A. 2
• B. 2.4
• C. 2.8
• D. Not determinable with the data

Answer 1

Answer: (B)

$ABCD$ is a trapezium.

$AB$ is parallel to $CD$.

$AB=11,BC=4,CD=6$ and $DA=3$

Construct $CE$ is parallel to $DA$.



$\therefore CE=3$

$BC=4$

$BE=5$

$\therefore \angle BCE$ is a right angled triangle.

$\therefore$ Area of $\Delta BCE=\frac{1}{2}EC\times BC$

$=\frac{1}{2}\times 3\times 4...(i)$

Also, area of

$\Delta BCE=\frac{1}{2}\times BE\times h$

$=\frac{1}{2}\times 5\times h...(ii)$

From Eqs. (i) and (ii),

$\frac{1}{2}\times 3\times 4=\frac{1}{2}\times 5\times h$

$\Rightarrow h=2.4$