Question

Let $A=\{x:x\in Z$ and $x^2\le 4\}$ and $B=\{x:x\in R$ and $x^2-3x+2=0\}$. Then,

• A. $A=B$
• B. $A\ne B$
• C. $A\in B$
• D. $A\notin B$

Answer 1

Answer: (B)

$A=\{-2,-1,0,1,2\}$
Given equation is $x^2-3x+2=0$
$\Rightarrow (x-1)(x-2)=0$
$\Rightarrow x=1,2$
$\therefore B=\{1,2\}$
Since, $0\in A$ and $0\notin B,A$ and $B$ are not equal sets.