Question

Let $A=\left\{x: x \in Z\right.$ and $\left.x^2 \leq 4\right\}$ and $B=\{x: x \in R$ and $\left.x^2-3 x+2=0\right\}$. Then,

• A. $A=B$
• B. $A \neq B$
• C. $A \in B$
• D. $A \notin B$

Answer 1

Answer: (B)

$A=\{-2,-1,0,1,2\}$
Given equation is $x^2-3 x+2=0$
$\Rightarrow (x-1)(x-2) =0$
$\Rightarrow x=1,2$
$ \therefore B =\{1,2\}$
Since, $0 \in A$ and $0 \notin B, A$ and $B$ are not equal sets.