Q.
Let a1,a2,a3 be three positive numbers which are in geometric progression with common ratio r . The inequality a3>a2+2a1 holds true if r is equal to
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NTA AbhyasNTA Abhyas 2020Sequences and Series
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Solution:
a2=a1r,a3=a1r2 a3>a2+2a1 ⇒a1r2>a1r+2a1 ⇒r2−r−2>0 ⇒(r−2)(r+1)>0 ⇒r<−1 or r>2