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Q. Let $a_{1},a_{2},a_{3}$ be three positive numbers which are in geometric progression with common ratio $r$ . The inequality $a_{3}>a_{2}+2a_{1}$ holds true if $r$ is equal to

NTA AbhyasNTA Abhyas 2020Sequences and Series

Solution:

$a_{2}=a_{1}r,a_{3}=a_{1}r^{2}$
$a_{3}>a_{2}+2a_{1}$
$\Rightarrow a_{1}r^{2}>a_{1}r+2a_{1}$
$\Rightarrow r^{2}-r-2>0$
$\Rightarrow \left(r - 2\right)\left(r + 1\right)>0$
$\Rightarrow r < -1$ or $r>2$