Let A=[1 -1 2 α] and B=[β 1 1 0], α, β ∈ R. Let α1 be the value of α which satisfies ( A + B )2= A 2+[2 2 2 2] and α2 be the value of α which satisfies (A+B)2=B2. Then |α1-α2| is equal to

Question

Let A=[1 -1 2 α] and B=[β 1 1 0], α, β ∈ R. Let α1 be the value of α which satisfies ( A + B )2= A 2+[2 2 2 2] and α2 be the value of α which satisfies (A+B)2=B2. Then |α1-α2| is equal to (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Q. Let A=[12​−1α​] and B=[β1​10​],α,β∈R. Let α1​ be the value of α which satisfies (A+B)2=A2+[22​22​] and α2​ be the value of α which satisfies (A+B)2=B2. Then ∣α1​−α2​∣ is equal to

Q. Let $A = [12 - 1 α]$ and $B = [β 1 10], α, β \in R$ . Let $α_{1}$ be the value of $α$ which satisfies $(A + B)^{2} = A^{2} + [2222]$ and $α_{2}$ be the value of $α$ which satisfies $(A + B)^{2} = B^{2}$ . Then $∣ α_{1} - α_{2} ∣$ is equal to