1. Tardigrade
  2. Question
  3. Mathematics
  4. Let A=[1 -1 2 α] and B=[β 1 1 0], α, β ∈ R. Let α1 be the value of α which satisfies ( A + B )2= A 2+[2 2 2 2] and α2 be the value of α which satisfies (A+B)2=B2. Then |α1-α2| is equal to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Let $A=\begin{bmatrix}1 & -1 \\ 2 & \alpha\end{bmatrix}$ and $B=\begin{bmatrix}\beta & 1 \\ 1 & 0\end{bmatrix}, \alpha, \beta \in R$. Let $\alpha_1$ be the value of $\alpha$ which satisfies $( A + B )^2= A ^2+\begin{bmatrix}2 & 2 \\ 2 & 2\end{bmatrix}$ and $\alpha_2$ be the value of $\alpha$ which satisfies $(A+B)^2=B^2$. Then $\left|\alpha_1-\alpha_2\right|$ is equal to

JEE MainJEE Main 2022Matrices

Solution:

image
image