Least count [.LC]. is the minimum length measured by a Vernier calipers and [Let us define Vernier constant (.VC.)=1MSD-1VSD.). Each main Scale division (MSD) of the calipers is 1mm and N divisions of main scale are divided into 10 Vernier scale divisions (.VSD.). If N=6, then LC=(k/10) (in mm ). Find k .

Question

Least count [.LC]. is the minimum length measured by a Vernier calipers and [Let us define Vernier constant (.VC.)=1MSD-1VSD.). Each main Scale division (MSD) of the calipers is 1mm and N divisions of main scale are divided into 10 Vernier scale divisions (.VSD.). If N=6, then LC=(k/10) (in mm ). Find k . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let 1VSD=x N Divisions of main scale coincides with 10 Vernier scale divisions so 10x=N× 110x=6x=0.6mm The Least count will be ⇒ 1MSD-1VSD⇒ 1-0.6⇒ 0.4mm

Let 1VSD=x N Divisions of main scale coincides with 10 Vernier scale divisions so 10x=N×110x=6x=0.6mm The Least count will be ⇒1MSD−1VSD⇒1−0.6⇒0.4mm

Let
$1 V S D = x$
$N$ Divisions of main scale coincides with $10$ Vernier scale divisions so
$10 x = N \times 110 x = 6 x = 0.6 mm$
The Least count will be
$\Rightarrow 1 MS D - 1 V S D \Rightarrow 1 - 0.6 \Rightarrow 0.4 mm$