KMnO 4 reacts with oxalic acid solution: 2 KMnO 4+3 H 2 SO 4+5 H 2 C 2 O 4 arrow K 2 SO 4+2 MnSO 4+10 CO 2+8 H 2 O What mass of KMnO 4 in aqueous solution will be required to completely react with 100 mL of M / 10 oxalic acid solution?

Question

KMnO 4 reacts with oxalic acid solution: 2 KMnO 4+3 H 2 SO 4+5 H 2 C 2 O 4 arrow K 2 SO 4+2 MnSO 4+10 CO 2+8 H 2 O What mass of KMnO 4 in aqueous solution will be required to completely react with 100 mL of M / 10 oxalic acid solution? (A) 10.53 g (B) 0.632 g (C) 3.105 g (D) 3.501 g

Tardigrade Admin · Accepted Answer

((M KMnO 4/ M KMnO 4) × 1000/( MV ) text oxalicacid )=(2/5) ( W KMnO 4/158) × 1000=(2/5) × (1/10) × 100 W KMnO 4=(2/5) × (1/10) × 100 × (158/1000) =0.632 g

Q. $K M n O_{4}$ reacts with oxalic acid solution:
$2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} C_{2} O_{4}$
$\to K_{2} S O_{4} + 2 M n S O_{4} + 10 C O_{2} + 8 H_{2} O$
What mass of $K M n O_{4}$ in aqueous solution will be required to completely react with $100 m L$ of $M /10$ oxalic acid solution?

10.53 g

0.632 g

3.105 g

3.501 g

$\frac{\frac{M _{K M n O_{4}}}{M _{K M n O_{4}}} \times 1000}{( M V ) _{oxalicacid}} = \frac{2}{5}$

$\frac{W _{K M n O_{4}}}{158} \times 1000 = \frac{2}{5} \times \frac{1}{10} \times 100$

$W_{K M n O_{4}} = \frac{2}{5} \times \frac{1}{10} \times 100 \times \frac{158}{1000}$

$= 0.632 g$

Q. KMnO4​ reacts with oxalic acid solution: 2KMnO4​+3H2​SO4​+5H2​C2​O4​ →K2​SO4​+2MnSO4​+10CO2​+8H2​O What mass of KMnO4​ in aqueous solution will be required to completely react with 100mL of M/10 oxalic acid solution?