KMnO4 reacts with ferrous sulphate according to the equation MnO-4 + 5Fe2+ + 8H+→ Mn2+ + 5Fe3+ + 4H2O. Here 10 mL of 0.1 M KMnO4 is equivalent to

Question

KMnO4 reacts with ferrous sulphate according to the equation MnO-4 + 5Fe2+ + 8H+→ Mn2+ + 5Fe3+ + 4H2O. Here 10 mL of 0.1 M KMnO4 is equivalent to (A) 30 mL of 0.1 M FeSO4 (B) 40 mL of 0.1 M FeSO4 (C) 20 mL of 0.1 M FeSO4 (D) 50 mL of 0.1 M FeSO4

Tardigrade Admin · Accepted Answer

In this reaction MnO-4 + 5Fe2+ + 8H+→ Mn2+ + 5Fe3+ + 4H2O 5 times quantity of Fe2+ consumed. Therefore, 5 times of FeSO4 will be equivalent to 50 mL.

Q. $K M n O_{4}$ reacts with ferrous sulphate according to the equation
$M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O$ . Here 10 mL of 0.1 M $K M n O_{4}$ is equivalent to

$30 m L$ of $0.1 M F e S O_{4}$

$40 m L$ of $0.1 M F e S O_{4}$

$20 m L$ of $0.1 M F e S O_{4}$

$50 m L$ of $0.1 M F e S O_{4}$

In this reaction
$M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O$
5 times quantity of $F e^{2 +}$ consumed. Therefore, 5 times of $F e S O_{4}$ will be equivalent to 50 mL.

Q. KMnO4​ reacts with ferrous sulphate according to the equation MnO4−​+5Fe2++8H+→Mn2++5Fe3++4H2​O. Here 10 mL of 0.1 M KMnO4​ is equivalent to

30mL of 0.1MFeSO4​

40mL of 0.1MFeSO4​

20mL of 0.1MFeSO4​

50mL of 0.1MFeSO4​