1. Tardigrade
  2. Question
  3. Chemistry
  4. KMnO4 reacts with ferrous sulphate according to the equation MnO-4 + 5Fe2+ + 8H+→ Mn2+ + 5Fe3+ + 4H2O. Here 10 mL of 0.1 M KMnO4 is equivalent to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $KMnO_4$ reacts with ferrous sulphate according to the equation
$MnO^{-}_{4 }+ 5Fe^{2+} + 8H^{+}\to Mn^{2+} + 5Fe^{3+} + 4H_{2}O$. Here 10 mL of 0.1 M $KMnO_4$ is equivalent to

The d-and f-Block Elements

Solution:

In this reaction
$MnO^{-}_{4 }+ 5Fe^{2+} + 8H^{+}\to Mn^{2+} + 5Fe^{3+} + 4H_{2}O$
5 times quantity of $Fe^{2+}$ consumed. Therefore, 5 times of $FeSO_4$ will be equivalent to 50 mL.