KMnO4 can be prepared from K2MnO4 as per the reaction: 3MnO42- + 2H2O leftharpoons 2MnO4- + MnO2 + 4OH- The reaction can go to completion by removing OH- ions by adding :

Question

KMnO4 can be prepared from K2MnO4 as per the reaction: 3MnO42- + 2H2O leftharpoons 2MnO4- + MnO2 + 4OH- The reaction can go to completion by removing OH- ions by adding : (A) SO2 (B) HCl (C) KOH (D) CO2

Tardigrade Admin · Accepted Answer

MnO4- oxidizes HCl and SO2 to Cl2 and SO3 respectively. MnO4- does not oxidizes H2CO3 (maximum oxidation state of C)

Q. $K M n O_{4}$ can be prepared from $K_{2} M n O_{4}$ as per the reaction :
$3 M n O_{4}^{2 -} + 2 H_{2} O ⇌ 2 M n O_{4}^{-} + M n O_{2} + 4 O H^{-}$
The reaction can go to completion by removing $O H^{-}$ ions by adding :

$S O_{2}$

$H Cl$

$K O H$

$C O_{2}$

$M n O_{4}^{-}$ oxidizes $H Cl$ and $S O_{2}$ to $C l_{2}$ and $S O_{3}$ respectively.
$M n O_{4}^{-}$ does not oxidizes $H_{2} C O_{3}$ (maximum oxidation state of $C$ )

Q. KMnO4​ can be prepared from K2​MnO4​ as per the reaction : 3MnO42−​+2H2​O⇌2MnO4−​+MnO2​+4OH− The reaction can go to completion by removing OH− ions by adding :

SO2​

HCl

KOH

CO2​