1. Tardigrade
  2. Question
  3. Chemistry
  4. KMnO4 can be prepared from K2MnO4 as per the reaction: 3MnO42- + 2H2O leftharpoons 2MnO4- + MnO2 + 4OH- The reaction can go to completion by removing OH- ions by adding :

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $KMnO_4$ can be prepared from $K_2MnO_4$ as per the reaction :
$3MnO_4^{2-} + 2H_2O \rightleftharpoons 2MnO_4^- + MnO_2 + 4OH^-$
The reaction can go to completion by removing $OH^-$ ions by adding :

NEETNEET 2013Equilibrium

Solution:

$MnO_4^{-}$ oxidizes $HCl$ and $SO_2$ to $Cl_{2}$ and $SO_3$ respectively.
$MnO_4^{-}$ does not oxidizes $H_2CO_3$ (maximum oxidation state of $C$)