Question

Kinetic energy of one mole of an ideal gas at 300 K in kJ is

• A. 34.8
• B. 3.48
• C. 3.74
• D. 348.

Answer 1

Answer: (C)

K.E. (per mole of an ideal gas)
= $\frac{3}{2}$RT
= $\frac{3}{2}\times (8.314J{K}^{-1}mo{l}^{-1})\times (300K)$
= 3741.3 J = 3.74 kJ