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  4. Kinetic energy of one mole of an ideal gas at 300 K in kJ is

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Q. Kinetic energy of one mole of an ideal gas at 300 K in kJ is

KCETKCET 2003States of Matter

Solution:

K.E. (per mole of an ideal gas)
= $\frac{3}{2} $RT
= $\frac{3}{2} \times (8.314\, JK^{-1} \, mol^{-1}) \times (300 K)$
= 3741.3 J = 3.74 kJ