Kc=9 for the reaction, A+B leftharpoons C+D. If A and B are taken in equal amounts, then amount of C. in equilibrium is :

Question

Kc=9 for the reaction, A+B leftharpoons C+D. If A and B are taken in equal amounts, then amount of C. in equilibrium is : (A) 1 (B) 0.25 (C) 0.75 (D) none of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/780154935720229cd801af8216a75ecc-.png" /> ∴ Kc=([C][D]/[A][B])=9 ∴ (x ⋅ x/(1-x)2)=9 or x2=9+9 x2-18 x or 8 x2-18 x+9=0 ∴ x=(3/2) or (3/4) Hence, among the given options, the option (c) i.e., 0.75 is correct.

Q. $K_{c} = 9$ for the reaction, $A + B ⇌ C + D$ . If $A$ and $B$ are taken in equal amounts, then amount of $C$ . in equilibrium is :

1

0.25

0.75

none of these

$∴ K_{c} = \frac{[ C ] [ D ]}{[ A ] [ B ]} = 9$
$∴ \frac{x \cdot x}{( 1 - x ) ^{2}} = 9$
or $x^{2} = 9 + 9 x^{2} - 18 x$
or $8 x^{2} - 18 x + 9 = 0$
$∴ x = \frac{3}{2}$
or $\frac{3}{4}$
Hence, among the given options, the option (c) i.e., $0.75$ is correct.

Q. Kc​=9 for the reaction, A+B⇌C+D. If A and B are taken in equal amounts, then amount of C. in equilibrium is :

1

0.25

0.75

none of these

∴Kc​=[A][B][C][D]​=9 ∴(1−x)2x⋅x​=9 orx2=9+9x2−18x or 8x2−18x+9=0 ∴x=23​ or 43​ Hence, among the given options, the option (c) i.e., 0.75 is correct.

Q. $K_{c} = 9$ for the reaction, $A + B ⇌ C + D$ . If $A$ and $B$ are taken in equal amounts, then amount of $C$ . in equilibrium is :

$∴ K_{c} = \frac{[ C ] [ D ]}{[ A ] [ B ]} = 9$
$∴ \frac{x \cdot x}{( 1 - x ) ^{2}} = 9$
or $x^{2} = 9 + 9 x^{2} - 18 x$
or $8 x^{2} - 18 x + 9 = 0$
$∴ x = \frac{3}{2}$
or $\frac{3}{4}$
Hence, among the given options, the option (c) i.e., $0.75$ is correct.