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Q.
$K_{c}=9$ for the reaction, $A+B \rightleftharpoons C+D$.
If $A$ and $B$ are taken in equal amounts, then amount of $C$. in equilibrium is :
Rajasthan PMTRajasthan PMT 2004
Solution:
$\therefore K_{c}=\frac{[C][D]}{[A][B]}=9 $
$ \therefore \frac{x \cdot x}{(1-x)^{2}}=9 $
or$ x^{2}=9+9 x^{2}-18 x $
or $8 x^{2}-18 x+9=0 $
$ \therefore x=\frac{3}{2} $
or $\frac{3}{4}$
Hence, among the given options, the option (c) i.e., $0.75$ is correct.
