Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Kb for weak base B is 1.0× 10- 6 then hydrolysis constant for the reaction B++H2O oversetleftharpoonsBOH+H+ is
Q.
K
b
for weak base
B
is
1.0
×
1
0
−
6
then hydrolysis constant for the reaction
B
+
+
H
2
O
⇌
BO
H
+
H
+
is
2015
173
NTA Abhyas
NTA Abhyas 2020
Equilibrium
Report Error
A
1
0
−
6
7%
B
1
0
−
7
3%
C
1
0
−
8
90%
D
1
0
−
9
0%
Solution:
B
+
+
H
2
O
⇌
BO
H
+
H
+
For hydrolysis of
B
+
the hydrolysis constant can be given as
K
H
=
K
b
K
w
=
1
0
−
6
1
0
−
14
=
1
0
−
8
.