Question

$K_{b}$ for weak base $B$ is $1.0\times 10^{- 6}$ then hydrolysis constant for the reaction

$B^{+}+H_{2}O\overset{}{\rightleftharpoons}BOH+H^{+}$ is

• A. $10^{- 6}$
• B. $10^{- 7}$
• C. $10^{- 8}$
• D. $10^{- 9}$

Answer 1

Answer: (C)

$B^{+}+H_{2}O\rightleftharpoons BOH+H^{+}$

For hydrolysis of $B^{+}$ the hydrolysis constant can be given as

$K_{H}=\frac{K_{w}}{K_{b}}$

$=\frac{1 0^{- 14}}{1 0^{- 6}}=10^{- 8}$ .