Isopropyl alcohol on treatment with excess of conc. H 2 SO 4 gives ' X ' which on treatment with HBr gives ' Y ' When ' Y ' is dissolved in ether and treated with sodium gives ' Z '. Caloulate the molecular weight of ' Z '.

Question

Isopropyl alcohol on treatment with excess of conc. H 2 SO 4 gives ' X ' which on treatment with HBr gives ' Y ' When ' Y ' is dissolved in ether and treated with sodium gives ' Z '. Caloulate the molecular weight of ' Z '. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/23d2249e522d325c95e17bc3b99c7c45-.png" /> Molecular weight of Z ( C 6 H 14) =6 × 12+14 × 1 =86 g mol -1

Q. Isopropyl alcohol on treatment with excess of conc. $H_{2} S O_{4}$ gives ' $X$ ' which on treatment with $H B r$ gives ' $Y$ ' When ' $Y$ ' is dissolved in ether and treated with sodium gives ' $Z$ '. Caloulate the molecular weight of ' $Z$ '.

Molecular weight of $Z (C_{6} H_{14}) = 6 \times 12 + 14 \times 1$
$= 86 g m o l^{- 1}$

Q. Isopropyl alcohol on treatment with excess of conc. H2​SO4​ gives ' X ' which on treatment with HBr gives ' Y ' When ' Y ' is dissolved in ether and treated with sodium gives ' Z '. Caloulate the molecular weight of ' Z '.

Molecular weight of Z(C6​H14​)=6×12+14×1 =86gmol−1

Q. Isopropyl alcohol on treatment with excess of conc. $H_{2} S O_{4}$ gives ' $X$ ' which on treatment with $H B r$ gives ' $Y$ ' When ' $Y$ ' is dissolved in ether and treated with sodium gives ' $Z$ '. Caloulate the molecular weight of ' $Z$ '.

Molecular weight of $Z (C_{6} H_{14}) = 6 \times 12 + 14 \times 1$
$= 86 g m o l^{- 1}$