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Q. Isopropyl alcohol on treatment with excess of conc. $H _{2} SO _{4}$ gives ' $X$ ' which on treatment with $HBr$ gives ' $Y$ ' When ' $Y$ ' is dissolved in ether and treated with sodium gives ' $Z$ '. Caloulate the molecular weight of ' $Z$ '.

Alcohols Phenols and Ethers

Solution:

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Molecular weight of $Z \left( C _{6} H _{14}\right) =6 \times 12+14 \times 1$
$=86\, g\, mol ^{-1}$