Question

$\underset{-1}{\overset{0}{\int }}\frac{dx}{2x+3}$ is equal to

• A. $log\frac{3}{2}$
• B. $log3-log1$
• C. $\frac{log3}{2}$
• D. $log3+log1$

Answer 1

Answer: (C)

We have, $I=\underset{-1}{\overset{0}{\int }}\frac{dx}{2x+3}$
${\left[\frac{log\left(2x+3\right)}{2}\right]}_{-1}^0=\left[\frac{log3}{2}-\frac{log1}{2}\right]=\frac{log3}{2}$