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Q. $ \int\limits_{-1}^{0}\frac{dx}{2x+3}$ is equal to

Integrals

Solution:

We have, $I = \int\limits_{-1}^{0} \frac{dx}{2x+3}$
$ \left[\frac{log\left(2x+3\right)}{2}\right]_{-1}^{0}=\left[\frac{log\,3}{2}-\frac{log\,1}{2}\right] =\frac{log\,3}{2}$