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Tardigrade
Question
Mathematics
∫ limits01 ( log (1+x)/1+x2) d x
Q.
0
∫
1
1
+
x
2
l
o
g
(
1
+
x
)
d
x
1832
245
Report Error
A
2
1
0%
B
8
π
lo
g
2
62%
C
2
π
lo
g
2
38%
D
4
π
lo
g
2
0%
Solution:
By substituting
x
=
tan
θ
I
=
0
∫
4
π
lo
g
(
1
+
tan
θ
)
d
θ
=
8
π
lo
g
2