Question

$\int \frac{e^{4x}-1}{e^{2x}}log(\frac{e^{2x}+1}{2^{2x}-1})dx$ $\frac{t^2}{2}logt-\frac{t^2}{4}-\frac{u^2}{2}logu+\frac{u^2}{4}+cthen$

• A. $t=u=e^x+e^{-x}$
• B. $t=e^x-e^{-x},u=e^x+e^{-x}$
• C. $t=e^x+e^{-x},u=e^x+e^{-x}$
• D. none of these.

Answer 1

Answer: (C)

Correct answer is (c) $t=e^x+e^{-x},u=e^x+e^{-x}$