1. Tardigrade
  2. Question
  3. Mathematics
  4. ∫ (e4x-1 /e2x) log ( (e2x+1 /22x-1))dx (t2 /2) log t - (t2 /4)- (u2 /2) log u+ (u2 /4)+c then

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $\int \frac {e^{4x}-1} {e^{2x}} log (\frac {e^{2x}+1} {2^{2x}-1})dx$ $\frac {t^2} {2} log\, t - \frac {t^2} {4}- \frac {u^2} {2} log \,u+ \frac {u^2} {4}+c \, then$

Solution:

Correct answer is (c) $t = e^x + e^{-x}, u = e^x + e^{-x}$