Question

Inequations $3x-y\ge 3$ and $4x-y\ge 4$

• A. Have solution for positive x and y
• B. Have no solution for positive x and y
• C. Have solution for all x
• D. Have solution for all y

Answer 1

Answer: (A)

Following figure will be obtained on drawing the graphs of given inequations.
From $3x-y\ge 3,\frac{x}{1}+\frac{y}{-3}=1$
From $4x-y>4,\frac{x}{1}+\frac{y}{-4}=1$
Clearly the common region of both is true for positive value of (x, y). It is also true for positive value of x and negative value of y.