Question

Inequations $3x - y \geq 3 $ and $4x - y \geq 4 $

• A. Have solution for positive x and y
• B. Have no solution for positive x and y
• C. Have solution for all x
• D. Have solution for all y

Answer 1

Answer: (A)

Following figure will be obtained on drawing the graphs of given inequations.
From $3x - y \geq 3, \frac{x}{1} + \frac{y}{-3} = 1 $
From $4x - y > 4, \frac{x}{1} + \frac{y}{-4} = 1$
Clearly the common region of both is true for positive value of (x, y). It is also true for positive value of x and negative value of y.