In Young’s double slit experiment a minima is observed when path difference between the interfering beam is :

Question

In Young’s double slit experiment a minima is observed when path difference between the interfering beam is : (A) λ  (B) 1.5 λ  (C) 2 λ  (D) 2.25 λ

Tardigrade Admin · Accepted Answer

The condition for minimum intensity, when the path difference is a multiple of half wavelengths, i.e., d sin θ=(n+(1/2)) λ So for the minima, n =1, ⇒ d sin θ=1.5 λ

Q. In Young’s double slit experiment a minima is observed when path difference between the interfering beam is :

$λ$

$1.5 λ$

$2 λ$

$2.25 λ$

The condition for minimum intensity, when the path difference is a multiple of half wavelengths,
i.e., $d sin θ = (n + \frac{1}{2}) λ$
So for the minima, $n = 1,$
$\Rightarrow d sin θ = 1.5 λ$

Q. In Young’s double slit experiment a minima is observed when path difference between the interfering beam is :

λ

1.5λ

2λ

2.25λ

The condition for minimum intensity, when the path difference is a multiple of half wavelengths, i.e., dsinθ=(n+21​)λ So for the minima, n=1, ⇒dsinθ=1.5λ

$λ$

$1.5 λ$

$2 λ$

$2.25 λ$

The condition for minimum intensity, when the path difference is a multiple of half wavelengths,
i.e., $d sin θ = (n + \frac{1}{2}) λ$
So for the minima, $n = 1,$
$\Rightarrow d sin θ = 1.5 λ$