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Q. In Young’s double slit experiment a minima is observed when path difference between the interfering beam is :

BITSATBITSAT 2006

Solution:

The condition for minimum intensity, when the path difference is a multiple of half wavelengths,
i.e., $d \sin \theta=\left(n+\frac{1}{2}\right) \lambda$
So for the minima, $n =1,$
$\Rightarrow d \sin \theta=1.5\, \lambda$