In YDSE distance between slits is 0.2 mm, distance between slit screen is 2 m and wavelength of monochromatic light incident on slit is 600 nm. The phase difference between the waves at a point 2 cm from mid point is (x π/3). Find x.

Question

In YDSE distance between slits is 0.2 mm, distance between slit screen is 2 m and wavelength of monochromatic light incident on slit is 600 nm. The phase difference between the waves at a point 2 cm from mid point is (x π/3). Find x. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ φ=2 π((d y/λ D))=2 π((2 × 10-4 × 2 × 10-2/6 × 10-7 × 2)) =(20 π/3)

Q. In YDSE distance between slits is $0.2 mm$ , distance between slit & screen is $2 m$ and wavelength of monochromatic light incident on slit is $600 nm$ . The phase difference between the waves at a point $2 c m$ from mid point is $\frac{x π}{3}$ . Find $x$ .

$Δ ϕ = 2 π (\frac{d y}{λ D}) = 2 π (\frac{2 \times 1 0 ^{- 4} \times 2 \times 1 0 ^{- 2}}{6 \times 1 0 ^{- 7} \times 2})$
$= \frac{20 π}{3}$

Q. In YDSE distance between slits is 0.2mm, distance between slit & screen is 2m and wavelength of monochromatic light incident on slit is 600nm. The phase difference between the waves at a point 2cm from mid point is 3xπ​. Find x.

Δϕ=2π(λDdy​)=2π(6×10−7×22×10−4×2×10−2​) =320π​

Q. In YDSE distance between slits is $0.2 mm$ , distance between slit & screen is $2 m$ and wavelength of monochromatic light incident on slit is $600 nm$ . The phase difference between the waves at a point $2 c m$ from mid point is $\frac{x π}{3}$ . Find $x$ .

$Δ ϕ = 2 π (\frac{d y}{λ D}) = 2 π (\frac{2 \times 1 0 ^{- 4} \times 2 \times 1 0 ^{- 2}}{6 \times 1 0 ^{- 7} \times 2})$
$= \frac{20 π}{3}$