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Q. In YDSE distance between slits is $0.2\, mm$, distance between slit & screen is $2\, m$ and wavelength of monochromatic light incident on slit is $600\, nm$. The phase difference between the waves at a point $2\, cm$ from mid point is $\frac{x \pi}{3}$. Find $x$.

Wave Optics

Solution:

$\Delta \phi=2 \pi\left(\frac{d y}{\lambda D}\right)=2 \pi\left(\frac{2 \times 10^{-4} \times 2 \times 10^{-2}}{6 \times 10^{-7} \times 2}\right)$
$=\frac{20 \pi}{3}$