In which of the following the magnetic character is not correct?

Question

In which of the following the magnetic character is not correct? (A) CuCl2-4 -1 unpaired electron (B) [Fe(H2O)6]2+ -5 unpaired electrons (C) [Zn(NH3)2]2+ -Diamagnetic (D) [CoF6]3--4 unpaired electrons

Tardigrade Admin · Accepted Answer

In [Fe(H2O)6]2+, the Fe(II) ion has 3d6 electronic configuration and pairing of electrons in 3d orbital does not take place due to the presence of weak field ligand, H2O. Hence, there are four unpaired electrons in [Fe(H2O)6 ]2+ ion.

Q. In which of the following the magnetic character is not correct?

$C u C l_{4}^{2 -} - 1$ unpaired electron

$[F e (H_{2} O)_{6}]^{2 +} - 5$ unpaired electrons

$[Z n (N H_{3})_{2}]^{2 +}$ -Diamagnetic

$[C o F_{6}]^{3 -} - 4$ unpaired electrons

In $[F e (H_{2} O)_{6}]^{2 +}$ , the Fe(II) ion has $3 d^{6}$ electronic configuration and pairing of electrons in 3d orbital does not take place due to the presence of weak field ligand, $H_{2} O .$
Hence, there are four unpaired electrons in $[F e (H_{2} O)_{6}]^{2 +}$ ion.

Q. In which of the following the magnetic character is not correct?

CuCl42−​−1 unpaired electron

[Fe(H2​O)6​]2+−5 unpaired electrons

[Zn(NH3​)2​]2+ -Diamagnetic

[CoF6​]3−−4 unpaired electrons

In [Fe(H2​O)6​]2+, the Fe(II) ion has 3d6 electronic configuration and pairing of electrons in 3d orbital does not take place due to the presence of weak field ligand, H2​O. Hence, there are four unpaired electrons in [Fe(H2​O)6​]2+ ion.

$C u C l_{4}^{2 -} - 1$ unpaired electron

$[F e (H_{2} O)_{6}]^{2 +} - 5$ unpaired electrons

$[Z n (N H_{3})_{2}]^{2 +}$ -Diamagnetic

$[C o F_{6}]^{3 -} - 4$ unpaired electrons

In $[F e (H_{2} O)_{6}]^{2 +}$ , the Fe(II) ion has $3 d^{6}$ electronic configuration and pairing of electrons in 3d orbital does not take place due to the presence of weak field ligand, $H_{2} O .$
Hence, there are four unpaired electrons in $[F e (H_{2} O)_{6}]^{2 +}$ ion.