Question

In which of the following the magnetic character is not correct?

• A. $CuCl^{2-}_{4} -1$ unpaired electron
• B. $[Fe(H_2O)_6]^{2+} -5$ unpaired electrons
• C. $[Zn(NH_3)_2]^{2+}$ -Diamagnetic
• D. $[CoF_6]^{3-}-4$ unpaired electrons

Answer 1

Answer: (B)

In $[Fe(H_2O)_6]^{2+}$, the Fe(II) ion has $3d^6$ electronic configuration and pairing of electrons in 3d orbital does not take place due to the presence of weak field ligand, $H_2O.$
Hence, there are four unpaired electrons in $[Fe(H_2O)_6 ]^{2+}$ ion.