In which of the following molecules are all the bonds not equal?

Question

In which of the following molecules are all the bonds not equal? (A)  ClF3  (B)  BF3  (C)  AlF3  (D)  NF3

Tardigrade Admin · Accepted Answer

In ClF3 all bonds are not equal due to trigonal bypyramidal ( sp3d- hybridisation) geometry of ClF3 molecule. BF3 and AlF3 show trigonal symmetric structure due to sp2- hybridisation. NF3 shows pyramidal geometry due to sp3 hybridisation

Q. In which of the following molecules are all the bonds not equal?

$Cl F_{3}$

$B F_{3}$

$A l F_{3}$

$N F_{3}$

In $Cl F_{3}$ all bonds are not equal due to trigonal bypyramidal ( $s p^{3} d -$ hybridisation) geometry of $Cl F_{3}$ molecule.
$B F_{3}$ and $A l F_{3}$ show trigonal symmetric structure due to $s p^{2} -$ hybridisation.
$N F_{3}$ shows pyramidal geometry due to $s p^{3}$ hybridisation

Q. In which of the following molecules are all the bonds not equal?

ClF3​

BF3​

AlF3​

NF3​

In ClF3​ all bonds are not equal due to trigonal bypyramidal ( sp3d− hybridisation) geometry of ClF3​ molecule. BF3​ and AlF3​ show trigonal symmetric structure due to sp2− hybridisation. NF3​ shows pyramidal geometry due to sp3 hybridisation

$Cl F_{3}$

$B F_{3}$

$A l F_{3}$

$N F_{3}$

In $Cl F_{3}$ all bonds are not equal due to trigonal bypyramidal ( $s p^{3} d -$ hybridisation) geometry of $Cl F_{3}$ molecule.
$B F_{3}$ and $A l F_{3}$ show trigonal symmetric structure due to $s p^{2} -$ hybridisation.
$N F_{3}$ shows pyramidal geometry due to $s p^{3}$ hybridisation