Question

In which of the following compounds the angle between two covalent bonds is highest?

• A. $C{H}_4$
• B. $N{H}_3$
• C. $H_{2}O$
• D. $H_2{O}_2$

Answer 1

Answer: (A)

$\text{C}{\text{H}}_{\text{4}}\text{,N}{\text{H}}_{\text{3}}$ and ${\text{H}}_{\text{2}}\text{O}$ all the three molecules shows $\text{s}{\text{p}}^3-$ hybridisation. In these molecules $\text{C}{\text{H}}_{\text{4}}$ has bond angle $\text{10}{\text{9}}^{\text{o}}$ 28 and have tetrahedral structure. But $\text{N}{\text{H}}_3$ and ${\text{H}}_{\text{2}}\text{O}$ has one and two lone pair of electrons respectively. Due to the presence of lone pair of electrons $\text{N}{\text{H}}_3$ and ${\text{H}}_{\text{2}}\text{O}$ their bond angle is decreased as $\text{10}{\text{7}}^{\text{o}}$ and $\text{10}{\text{4}}^{\text{o}}$ respectively and have pyramidal and V shape respectively. Hence, the angle is maximum in $\text{C}{\text{H}}_4.$