In veiw of the signs of ΔrG° for the following reactions: PbO2 + Pb → 2PbO, ΔrG° 0, which oxidation states are more characteristics for lead and tin ?

Question

In veiw of the signs of ΔrG° for the following reactions: PbO2 + Pb → 2PbO, ΔrG° < 0 SnO2 + Sn → 2SnO, ΔrG° > 0, which oxidation states are more characteristics for lead and tin ? (A) For lead +2, for tin +2 (B) For lead +4, for tin +4 (C) For lead +2, for tin +4 (D) For lead +4, for tin +2

Tardigrade Admin · Accepted Answer

Negative ΔrG° value indicates that + 2 oxidation state is more stable for Pb2+. Also it is supported by inert pair effect that +2 oxidation state is more stable for Pb and + 4 oxidation state is more stable for Sn.

Q. In veiw of the signs of $Δ_{r} G^{\circ}$ for the following reactions :
$P b O_{2} + P b \to 2 P b O, Δ_{r} G^{\circ} < 0$
$S n O_{2} + S n \to 2 S n O, Δ_{r} G^{\circ} > 0,$
which oxidation states are more characteristics for lead and tin ?

For lead +2, for tin +2

For lead +4, for tin +4

For lead +2, for tin +4

For lead +4, for tin +2

Negative $Δ_{r} G^{\circ}$ value indicates that + 2 oxidation state is more stable for $P b^{2 +}$ . Also it is supported by inert pair effect that +2 oxidation state is more stable for Pb and + 4 oxidation state is more stable for Sn.

Q. In veiw of the signs of Δr​G∘ for the following reactions : PbO2​+Pb→2PbO,Δr​G∘<0 SnO2​+Sn→2SnO,Δr​G∘>0, which oxidation states are more characteristics for lead and tin ?