In this reaction, CH 3 CHO + HCN arrow CH 3 CH ( OH ) CN xrightarrow text H.OH CH 3 CH ( OH ) COOH an asymmetric centre is generated. The acid obtained would be

Question

In this reaction, CH 3 CHO + HCN arrow CH 3 CH ( OH ) CN xrightarrow text H.OH CH 3 CH ( OH ) COOH an asymmetric centre is generated. The acid obtained would be (A) 50% D + 50% L-isomer (B) 20% D + 80% L-isomer (C) D-isomer (D) L-isomer

Tardigrade Admin · Accepted Answer

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exits as d and 1-forms whose ratio is 1: 1.

Q. In this reaction,
$C H_{3} C H O + H CN \to C H_{3} C H (O H) CN H.OH C H_{3} C H (O H) COO H$
an asymmetric centre is generated. The acid obtained would be

50% D + 50% L-isomer

20% D + 80% L-isomer

D-isomer

L-isomer

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral $C$ -atom. It exits as d and $1$ -forms whose ratio is $1 : 1.$

Q. In this reaction, CH3​CHO+HCN→CH3​CH(OH)CN H.OH ​CH3​CH(OH)COOH an asymmetric centre is generated. The acid obtained would be