1. Tardigrade
  2. Question
  3. Chemistry
  4. In this reaction, CH 3 CHO + HCN arrow CH 3 CH ( OH ) CN xrightarrow text H.OH CH 3 CH ( OH ) COOH an asymmetric centre is generated. The acid obtained would be

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Q. In this reaction,
$CH _{3} CHO + HCN \rightarrow CH _{3} CH ( OH ) CN\xrightarrow{\text { H.OH }} CH _{3} CH ( OH ) COOH$
an asymmetric centre is generated. The acid obtained would be

AIPMTAIPMT 2003Aldehydes Ketones and Carboxylic Acids

Solution:

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral $C$-atom. It exits as d and $1$-forms whose ratio is $1 : 1.$

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