Question

In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda$ then radius of third orbit is :-

• A. $3\lambda$
• B. $\lambda$
• C. $\frac{3\lambda }{2\pi }$
• D. $\frac{\lambda }{2\pi }$

Answer 1

Answer: (C)

$2\pi r_n=n\lambda$
$\Rightarrow r_n=\frac{n\lambda }{2\pi }$
$r_3=\frac{3\lambda }{2\pi }$