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  4. In third orbit of hydrogen atom, de Broglie wavelength of electron is λ then radius of third orbit is :-

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Q. In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda$ then radius of third orbit is :-

Solution:

$2 \pi r_{n}=n \lambda$
$\Rightarrow r_{n}=\frac{n \lambda}{2 \pi}$
$r_{3}=\frac{3 \lambda}{2 \pi}$