In the Wheatstone's bridge shown below, in order to balance the bridge we must have:

Question

In the Wheatstone's bridge shown below, in order to balance the bridge we must have: (A) R1=3 Ω, R2=3 Ω (B) R1=6 Ω, R2=1.5 Ω (C) R1=1.5 Ω, R2= any finite value (D) R1=3 Ω, R2= any finite value

Tardigrade Admin · Accepted Answer

Given circuit is a balanced Wheatstone's bridge. The ratio of resistances in the opposite arms of the circuit is equal i.e., (10/30)=(R1/9) ⇒ R1=3 Ω and resistance R2 may have any finite value.

Q. In the Wheatstone's bridge shown below, in order to balance the bridge we must have:

$R_{1} = 3 Ω, R_{2} = 3 Ω$

$R_{1} = 6 Ω, R_{2} = 1.5 Ω$

$R_{1} = 1.5 Ω, R_{2} =$ any finite value

$R_{1} = 3 Ω, R_{2} =$ any finite value

Given circuit is a balanced Wheatstone's bridge.
The ratio of resistances in the opposite arms of the circuit is equal i.e.,
$\frac{10}{30} = \frac{R _{1}}{9}$
$\Rightarrow R_{1} = 3 Ω$ and resistance $R_{2}$
may have any finite value.

Q. In the Wheatstone's bridge shown below, in order to balance the bridge we must have:

R1​=3Ω,R2​=3Ω

R1​=6Ω,R2​=1.5Ω

R1​=1.5Ω,R2​= any finite value

R1​=3Ω,R2​= any finite value

Given circuit is a balanced Wheatstone's bridge. The ratio of resistances in the opposite arms of the circuit is equal i.e., 3010​=9R1​​ ⇒R1​=3Ω and resistance R2​ may have any finite value.

$R_{1} = 3 Ω, R_{2} = 3 Ω$

$R_{1} = 6 Ω, R_{2} = 1.5 Ω$

$R_{1} = 1.5 Ω, R_{2} =$ any finite value

$R_{1} = 3 Ω, R_{2} =$ any finite value

Given circuit is a balanced Wheatstone's bridge.
The ratio of resistances in the opposite arms of the circuit is equal i.e.,
$\frac{10}{30} = \frac{R _{1}}{9}$
$\Rightarrow R_{1} = 3 Ω$ and resistance $R_{2}$
may have any finite value.