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Q.
In the Wheatstone's bridge shown below, in order to balance the bridge we must have:
Jharkhand CECEJharkhand CECE 2005
Solution:
Given circuit is a balanced Wheatstone's bridge.
The ratio of resistances in the opposite arms of the circuit is equal i.e.,
$\frac{10}{30}=\frac{R_{1}}{9} $
$\Rightarrow R_{1}=3 \,\Omega $ and resistance $ R_{2}$
may have any finite value.