In the uranium radioactive series, the initial nucleus is 92U238 and that the final nucleus is 82Pb206. When uranium nucleus decays to lead, the number of a particles and b particles emitted are

Question

In the uranium radioactive series, the initial nucleus is 92U238 and that the final nucleus is 82Pb206. When uranium nucleus decays to lead, the number of a particles and b particles emitted are (A)  8 α , 6 β (B)  6 α , 7 β (C)  6 α , 8 β (D)  4 α , 3 β

Tardigrade Admin · Accepted Answer

Let no. of α particles emitted be x and no. of β particles emitted be y. Difference in mass no. 4 x = 238 - 206 = 32 x = 8 Difference in charge no. 2x - 1y = 92 - 82 = 10 16 - y = 10 or y = 6

Q. In the uranium radioactive series, the initial nucleus is $_{92} U^{238}$ and that the final nucleus is $_{82} P b^{206}$ . When uranium nucleus decays to lead, the number of a particles and b particles emitted are

$8 α, 6 β$

$6 α, 7 β$

$6 α, 8 β$

$4 α, 3 β$

Let no. of $α$ particles emitted be $x$ and no. of $β$ particles emitted be $y$ .
Difference in mass no. $4 x = 238 - 206 = 32$
$x = 8$
Difference in charge no. $2 x - 1 y = 92 - 82 = 10$
$16 - y = 10$ or $y = 6$

Q. In the uranium radioactive series, the initial nucleus is 92​U238 and that the final nucleus is 82​Pb206. When uranium nucleus decays to lead, the number of a particles and b particles emitted are

8α,6β

6α,7β

6α,8β

4α,3β